6x^2-35x-72=0

Solution for 6x^2-35x-72=0 equation:

6x^2-35x-72=0

a = 6; b = -35; c = -72;
Δ = b2-4ac
Δ = -352-4·6·(-72)
Δ = 2953
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{2953}}{2*6}=\frac{35-\sqrt{2953}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{2953}}{2*6}=\frac{35+\sqrt{2953}}{12}
$